Look at the following program
main( )
{
int i = 20 ;
display ( i ) ;
}
display ( int j )
{
int k = 35 ;
printf ( "\n%d", j ) ;
printf ( "\n%d", k ) ;
}
main( )
{
int i = 20 ;
display ( i ) ;
}
display ( int j )
{
int k = 35 ;
printf ( "\n%d", j ) ;
printf ( "\n%d", k ) ;
}
of i is known only to the function main( ) and not to any other function. Similarly, the variable k is local to the function display( ) and hence it is not available to main( ). That is why to make the value of i available to display( ) we have to explicitly pass it to display( ). Likewise, if we want k to be available to main( ) we will have to return it to main( ) using the return statement. In general we can say that the scope of a variable is local to the function in which it is defined.
In this program is it necessary to pass the value of the variable i to the function display( )? Will it not become automatically available to the function display( )? No. Because by default the scope of a variable is local to the function in which it is defined. The presence
In this program is it necessary to pass the value of the variable i to the function display( )? Will it not become automatically available to the function display( )? No. Because by default the scope of a variable is local to the function in which it is defined. The presence
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